tolong pake cara yaa
Jawab:
Penjelasan dengan langkah-langkah:
[tex](\frac{1}{4})^{x-1} = \sqrt[3]{2^{3x+1}}\\ \\ (2^{-2})^{x-1} = {2^\frac{3x+1}{3}}\\ \\2^{-2x+2} = {2^\frac{3x+1}{3}}\\ \\ -2x+2 = \frac{3x+1}{3}\\ \\-6x+6 = 3x+1\\ \\5=9x\\ \\ x = \frac{5}{9}[/tex]
[answer.2.content]
