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6. ∫ 4/x² dx = ∫ 4x⁻² dx
[tex] = \frac{4}{ - 2 + 1} x {}^{ - 2 + 1} + c \\ = \frac{4}{ - 1} x {}^{ - 1} + c \\ = - 4x {}^{ - 1} + c \\ = - \frac{4}{x} + c(c.)[/tex]
[answer.2.content]
6. ∫ 4/x² dx = ∫ 4x⁻² dx
[tex] = \frac{4}{ - 2 + 1} x {}^{ - 2 + 1} + c \\ = \frac{4}{ - 1} x {}^{ - 1} + c \\ = - 4x {}^{ - 1} + c \\ = - \frac{4}{x} + c(c.)[/tex]
[answer.2.content]